Question
$$(5p-3)(2p-4) = 0$$
Answer
$$ \begin{matrix}p_1 = 2 & p_2 = \dfrac{ 3 }{ 5 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (5p-3)(2p-4) &= 0&& \text{simplify left side} \\[1 em]10p^2-20p-6p+12 &= 0&& \\[1 em]10p^2-26p+12 &= 0&& \\[1 em] \end{aligned} $$
$ 10x^{2}-26x+12 = 0 $ is a quadratic equation.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this equation.
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