Question
$$(5-a)(3a+7) = 0$$
Answer
$$ \begin{matrix}a_1 = 5 & a_2 = -\dfrac{ 7 }{ 3 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (5-a)(3a+7) &= 0&& \text{simplify left side} \\[1 em]15a+35-3a^2-7a &= 0&& \\[1 em]-3a^2+8a+35 &= 0&& \\[1 em] \end{aligned} $$
$ -3x^{2}+8x+35 = 0 $ is a quadratic equation.
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