Question
$$(5+2)^2-9x\cdot3+2^3 = 0$$
Answer
$$ x = \dfrac{19}{9} $$
Explanation
$$ \begin{aligned} (5+2)^2-9x\cdot3+2^3 &= 0&& \text{simplify left side} \\[1 em]7^2-27x+2^3 &= 0&& \\[1 em]49-27x+8 &= 0&& \\[1 em]-27x+57 &= 0&& \text{ move the constants to the right } \\[1 em]-27x &= -57&& \text{ divide both sides by $ -27 $ } \\[1 em]x &= \frac{-57}{-27}&& \\[1 em]x &= \frac{19}{9}&& \\[1 em] \end{aligned} $$
This page was created using
Equations Solver