$$ \begin{aligned} (4x+1)(3x+37) &= 35&& \text{simplify left side} \\[1 em]12x^2+148x+3x+37 &= 35&& \\[1 em]12x^2+151x+37 &= 35&& \text{move all terms to the left hand side } \\[1 em]12x^2+151x+37-35 &= 0&& \text{simplify left side} \\[1 em]12x^2+151x+2 &= 0&& \\[1 em] \end{aligned} $$
$ 12x^{2}+151x+2 = 0 $ is a quadratic equation.
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