Question
$$(4x-5)(x-3) = 0$$
Answer
$$ \begin{matrix}x_1 = 3 & x_2 = \dfrac{ 5 }{ 4 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (4x-5)(x-3) &= 0&& \text{simplify left side} \\[1 em]4x^2-12x-5x+15 &= 0&& \\[1 em]4x^2-17x+15 &= 0&& \\[1 em] \end{aligned} $$
$ 4x^{2}-17x+15 = 0 $ is a quadratic equation.
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