Question
$$(4x-4)(4x+4) = 0$$
Answer
$$ \begin{matrix}x_1 = 1 & x_2 = -1 \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (4x-4)(4x+4) &= 0&& \text{simplify left side} \\[1 em]16x^2+16x-16x-16 &= 0&& \\[1 em]16x^2+16x-16x-16 &= 0&& \\[1 em]16x^2-16 &= 0&& \\[1 em] \end{aligned} $$
$ 16x^{2}-16 = 0 $ is a quadratic equation.
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