Question
$$(4+3x+1)\cdot(4-(3x+1)) = 0$$
Answer
$$ \begin{matrix}x_1 = 1 & x_2 = -\dfrac{ 5 }{ 3 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (4+3x+1)\cdot(4-(3x+1)) &= 0&& \text{simplify left side} \\[1 em](3x+5)\cdot(4-(3x+1)) &= 0&& \\[1 em](3x+5)(4-3x-1) &= 0&& \\[1 em](3x+5)(-3x+3) &= 0&& \\[1 em]-9x^2+9x-15x+15 &= 0&& \\[1 em]-9x^2-6x+15 &= 0&& \\[1 em] \end{aligned} $$
$ -9x^{2}-6x+15 = 0 $ is a quadratic equation.
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