Question
$$(4-z)(4z+2) = 0$$
Answer
$$ \begin{matrix}z_1 = -\dfrac{ 1 }{ 2 } & z_2 = 4 \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (4-z)(4z+2) &= 0&& \text{simplify left side} \\[1 em]16z+8-4z^2-2z &= 0&& \\[1 em]-4z^2+14z+8 &= 0&& \\[1 em] \end{aligned} $$
$ -4x^{2}+14x+8 = 0 $ is a quadratic equation.
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