Question
$$(3x+8)(x-3) = 0$$
Answer
$$ \begin{matrix}x_1 = 3 & x_2 = -\dfrac{ 8 }{ 3 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (3x+8)(x-3) &= 0&& \text{simplify left side} \\[1 em]3x^2-9x+8x-24 &= 0&& \\[1 em]3x^2-x-24 &= 0&& \\[1 em] \end{aligned} $$
$ 3x^{2}-x-24 = 0 $ is a quadratic equation.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this equation.
This page was created using
Equations Solver