Question
$$(3x+5x-2)(2x-3x+4) = 0$$
Answer
$$ \begin{matrix}x_1 = \dfrac{ 1 }{ 4 } & x_2 = 4 \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (3x+5x-2)(2x-3x+4) &= 0&& \text{simplify left side} \\[1 em](8x-2)(-x+4) &= 0&& \\[1 em]-8x^2+32x+2x-8 &= 0&& \\[1 em]-8x^2+34x-8 &= 0&& \\[1 em] \end{aligned} $$
$ -8x^{2}+34x-8 = 0 $ is a quadratic equation.
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