Question
$$(3x-8)(x+2) = 0$$
Answer
$$ \begin{matrix}x_1 = -2 & x_2 = \dfrac{ 8 }{ 3 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (3x-8)(x+2) &= 0&& \text{simplify left side} \\[1 em]3x^2+6x-8x-16 &= 0&& \\[1 em]3x^2-2x-16 &= 0&& \\[1 em] \end{aligned} $$
$ 3x^{2}-2x-16 = 0 $ is a quadratic equation.
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