Question
$$(3x-5)(3x+2) = 0$$
Answer
$$ \begin{matrix}x_1 = -\dfrac{ 2 }{ 3 } & x_2 = \dfrac{ 5 }{ 3 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (3x-5)(3x+2) &= 0&& \text{simplify left side} \\[1 em]9x^2+6x-15x-10 &= 0&& \\[1 em]9x^2-9x-10 &= 0&& \\[1 em] \end{aligned} $$
$ 9x^{2}-9x-10 = 0 $ is a quadratic equation.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this equation.
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