Question
$$(3x-1)(2x-1) = 0$$
Answer
$$ \begin{matrix}x_1 = \dfrac{ 1 }{ 2 } & x_2 = \dfrac{ 1 }{ 3 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (3x-1)(2x-1) &= 0&& \text{simplify left side} \\[1 em]6x^2-3x-2x+1 &= 0&& \\[1 em]6x^2-5x+1 &= 0&& \\[1 em] \end{aligned} $$
$ 6x^{2}-5x+1 = 0 $ is a quadratic equation.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this equation.
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