Question
$$\frac{3x^2-x}{x-1} = 0$$
Answer
$$ \begin{matrix}x_1 = 0 & x_2 = \dfrac{ 1 }{ 3 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} \frac{3x^2-x}{x-1} &= 0&& \text{multiply ALL terms by } \color{blue}{ x-1 }. \\[1 em](x-1)\frac{3x^2-x}{x-1} &= (x-1)\cdot0&& \text{cancel out the denominators} \\[1 em]3x^2-x &= 0&& \\[1 em] \end{aligned} $$
In order to solve $ \color{blue}{ 3x^{2}-x = 0 } $, first we need to factor our $ x $.
$$ 3x^{2}-x = x \left( 3x-1 \right) $$$ x = 0 $ is a root of multiplicity $ 1 $.
The second root can be found by solving equation $ 3x-1 = 0$.
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