Question
$$3x^2-10-(-3x^2+4) = 0$$
Answer
$$ \begin{matrix}x_1 = - \dfrac{\sqrt{ 21 }}{ 3 } & x_2 = \dfrac{\sqrt{ 21 }}{ 3 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} 3x^2-10-(-3x^2+4) &= 0&& \text{simplify left side} \\[1 em]3x^2-10+3x^2-4 &= 0&& \\[1 em]6x^2-14 &= 0&& \\[1 em] \end{aligned} $$
$ 6x^{2}-14 = 0 $ is a quadratic equation.
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