Question
$$(3u-2)\cdot(9-u) = 0$$
Answer
$$ \begin{matrix}u_1 = \dfrac{ 2 }{ 3 } & u_2 = 9 \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (3u-2)\cdot(9-u) &= 0&& \text{simplify left side} \\[1 em]27u-3u^2-18+2u &= 0&& \\[1 em]-3u^2+29u-18 &= 0&& \\[1 em] \end{aligned} $$
$ -3x^{2}+29x-18 = 0 $ is a quadratic equation.
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