Question
$$(3g^9+6g^3+5)(g^4-2) = 0$$
Answer
This equation has no solution.
Explanation
$$ \begin{aligned} (3g^9+6g^3+5)(g^4-2) &= 0&& \text{simplify left side} \\[1 em]3g^{13}-6g^9+6g^7-12g^3+5g^4-10 &= 0&& \\[1 em]3g^{13}-6g^9+6g^7+5g^4-12g^3-10 &= 0&& \\[1 em] \end{aligned} $$
This polynomial has no rational roots that can be found using Rational Root Test.
Roots were found using Newton method.
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