Question
$$3a+4-8a-(2+5a) = 0$$
Answer
$$ a = \dfrac{1}{5} $$
Explanation
$$ \begin{aligned} 3a+4-8a-(2+5a) &= 0&& \text{simplify left side} \\[1 em]-5a+4-(2+5a) &= 0&& \\[1 em]-5a+4-2-5a &= 0&& \\[1 em]-10a+2 &= 0&& \text{ move the constants to the right } \\[1 em]-10a &= -2&& \text{ divide both sides by $ -10 $ } \\[1 em]a &= \frac{-2}{-10}&& \\[1 em]a &= \frac{1}{5}&& \\[1 em] \end{aligned} $$
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