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Question
$$(\frac{3}{4}+\frac{1}{3})\frac{\frac{\frac{41}{3}}{31}}{3} = 0$$
Answer
This equation has no solution.
Explanation
$$ \begin{aligned} (\frac{3}{4}+\frac{1}{3})\frac{\frac{\frac{41}{3}}{31}}{3} &= 0&& \text{simplify left side} \\[1 em]\frac{13}{12}\frac{\frac{\frac{41}{3}}{31}}{3} &= 0&& \text{multiply ALL terms by } \color{blue}{ 372 }. \\[1 em]372 \cdot \frac{13}{12}\frac{\frac{\frac{41}{3}}{31}}{3} &= 372\cdot0&& \text{cancel out the denominators} \\[1 em]\frac{533}{9} &= 0&& \\[1 em] \end{aligned} $$
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