Question
$$(2x+4)(3x-2) = 0$$
Answer
$$ \begin{matrix}x_1 = -2 & x_2 = \dfrac{ 2 }{ 3 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (2x+4)(3x-2) &= 0&& \text{simplify left side} \\[1 em]6x^2-4x+12x-8 &= 0&& \\[1 em]6x^2+8x-8 &= 0&& \\[1 em] \end{aligned} $$
$ 6x^{2}+8x-8 = 0 $ is a quadratic equation.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this equation.
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