Question
$$(2x+3)^2-(2x-3)^2 = 0$$
Answer
$$ x = 0 $$
Explanation
$$ \begin{aligned} (2x+3)^2-(2x-3)^2 &= 0&& \text{simplify left side} \\[1 em]4x^2+12x+9-(4x^2-12x+9) &= 0&& \\[1 em]4x^2+12x+9-4x^2+12x-9 &= 0&& \\[1 em]4x^2+12x+9-4x^2+12x-9 &= 0&& \\[1 em]24x &= 0&& \text{ divide both sides by $ 24 $ } \\[1 em]x &= \frac{0}{24}&& \\[1 em]x &= 0&& \\[1 em] \end{aligned} $$
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