Question
$$(2x\cdot2+3x-1)^2-10x\cdot2-15x+9 = 0$$
Answer
$$ \begin{matrix}x_1 = \dfrac{ 2 }{ 7 } & x_2 = \dfrac{ 5 }{ 7 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (2x\cdot2+3x-1)^2-10x\cdot2-15x+9 &= 0&& \text{simplify left side} \\[1 em](4x+3x-1)^2-20x-15x+9 &= 0&& \\[1 em](7x-1)^2-20x-15x+9 &= 0&& \\[1 em]49x^2-14x+1-20x-15x+9 &= 0&& \\[1 em]49x^2-49x+10 &= 0&& \\[1 em] \end{aligned} $$
$ 49x^{2}-49x+10 = 0 $ is a quadratic equation.
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