Question
$$(2x-5)(x+1) = 0$$
Answer
$$ \begin{matrix}x_1 = -1 & x_2 = \dfrac{ 5 }{ 2 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (2x-5)(x+1) &= 0&& \text{simplify left side} \\[1 em]2x^2+2x-5x-5 &= 0&& \\[1 em]2x^2-3x-5 &= 0&& \\[1 em] \end{aligned} $$
$ 2x^{2}-3x-5 = 0 $ is a quadratic equation.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this equation.
This page was created using
Equations Solver