Question
$$2x\cdot2-6x-5-9x\cdot2+5x-4 = 0$$
Answer
$$ x = -\dfrac{3}{5} $$
Explanation
$$ \begin{aligned} 2x\cdot2-6x-5-9x\cdot2+5x-4 &= 0&& \text{simplify left side} \\[1 em]4x-6x-5-18x+5x-4 &= 0&& \\[1 em]-2x-5-13x-4 &= 0&& \\[1 em]-15x-9 &= 0&& \text{ move the constants to the right } \\[1 em]-15x &= 9&& \text{ divide both sides by $ -15 $ } \\[1 em]x &= -\frac{9}{15}&& \\[1 em]x &= -\frac{3}{5}&& \\[1 em] \end{aligned} $$
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