Question
$$2x^2+3x+2-(x^2+2x-3) = 0$$
Answer
$$ \begin{matrix}x_1 = -\dfrac{ 1 }{ 2 }+\dfrac{\sqrt{ 19 }}{ 2 }i & x_2 = -\dfrac{ 1 }{ 2 }-\dfrac{\sqrt{ 19 }}{ 2 }i \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} 2x^2+3x+2-(x^2+2x-3) &= 0&& \text{simplify left side} \\[1 em]2x^2+3x+2-x^2-2x+3 &= 0&& \\[1 em]x^2+x+5 &= 0&& \\[1 em] \end{aligned} $$
$ x^{2}+x+5 = 0 $ is a quadratic equation.
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