Question
$$2x^2-3x+7-(5x^2+3x+6) = 0$$
Answer
$$ \begin{matrix}x_1 = -1-\dfrac{ 2 \sqrt{ 3}}{ 3 } & x_2 = -1+\dfrac{ 2 \sqrt{ 3}}{ 3 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} 2x^2-3x+7-(5x^2+3x+6) &= 0&& \text{simplify left side} \\[1 em]2x^2-3x+7-5x^2-3x-6 &= 0&& \\[1 em]-3x^2-6x+1 &= 0&& \\[1 em] \end{aligned} $$
$ -3x^{2}-6x+1 = 0 $ is a quadratic equation.
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