Question
$$2x^2-8x-\frac{129}{50} = 0$$
Answer
$$ \begin{matrix}x_1 = -\dfrac{ 3 }{ 10 } & x_2 = \dfrac{ 43 }{ 10 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} 2x^2-8x-\frac{129}{50} &= 0&& \text{multiply ALL terms by } \color{blue}{ 50 }. \\[1 em]50\cdot2x^2-50\cdot8x-50\cdot\frac{129}{50} &= 50\cdot0&& \text{cancel out the denominators} \\[1 em]100x^2-400x-129 &= 0&& \\[1 em] \end{aligned} $$
$ 100x^{2}-400x-129 = 0 $ is a quadratic equation.
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