Question
$$(20x-29)^2 = 441$$
Answer
$$ \begin{matrix}x_1 = \dfrac{ 2 }{ 5 } & x_2 = \dfrac{ 5 }{ 2 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (20x-29)^2 &= 441&& \text{simplify left side} \\[1 em]400x^2-1160x+841 &= 441&& \text{move all terms to the left hand side } \\[1 em]400x^2-1160x+841-441 &= 0&& \text{simplify left side} \\[1 em]400x^2-1160x+400 &= 0&& \\[1 em] \end{aligned} $$
$ 400x^{2}-1160x+400 = 0 $ is a quadratic equation.
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