Question
$$\frac{{2^2}^2}{4}\cdot(3-1) = 0$$
Answer
This equation has no solution.
Explanation
$$ \begin{aligned} \frac{{2^2}^2}{4}\cdot(3-1) &= 0&& \text{simplify left side} \\[1 em]\frac{{2^2}^2}{4}\cdot2 &= 0&& \text{multiply ALL terms by } \color{blue}{ 4 }. \\[1 em]4 \cdot \frac{{2^2}^2}{4}\cdot2 &= 4\cdot0&& \text{cancel out the denominators} \\[1 em]32 &= 0&& \\[1 em] \end{aligned} $$
Since the statement $ \color{red}{ 32 = 0 } $ is FALSE, we conclude that the equation has no solution.
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