Question
$$(15-3x)\cdot(15-3x) = 2x+1$$
Answer
$$ \begin{matrix}x_1 = 4 & x_2 = \dfrac{ 56 }{ 9 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (15-3x)\cdot(15-3x) &= 2x+1&& \text{simplify left side} \\[1 em]225-45x-45x+9x^2 &= 2x+1&& \\[1 em]9x^2-90x+225 &= 2x+1&& \text{move all terms to the left hand side } \\[1 em]9x^2-90x+225-2x-1 &= 0&& \text{simplify left side} \\[1 em]9x^2-92x+224 &= 0&& \\[1 em] \end{aligned} $$
$ 9x^{2}-92x+224 = 0 $ is a quadratic equation.
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