$$ \begin{aligned} 10x+10-(7x\cdot2+5x-8) &= 0&& \text{simplify left side} \\[1 em]10x+10-(14x+5x-8) &= 0&& \\[1 em]10x+10-(19x-8) &= 0&& \\[1 em]10x+10-19x+8 &= 0&& \\[1 em]-9x+18 &= 0&& \text{ move the constants to the right } \\[1 em]-9x &= -18&& \text{ divide both sides by $ -9 $ } \\[1 em]x &= \frac{-18}{-9}&& \\[1 em]x &= 2&& \\[1 em] \end{aligned} $$

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