Question
$$(10-2)\cdot(4-6x) = 0$$
Answer
$$ x = \dfrac{2}{3} $$
Explanation
$$ \begin{aligned} (10-2)\cdot(4-6x) &= 0&& \text{simplify left side} \\[1 em]8\cdot(4-6x) &= 0&& \\[1 em]32-48x &= 0&& \\[1 em]-48x+32 &= 0&& \text{ move the constants to the right } \\[1 em]-48x &= -32&& \text{ divide both sides by $ -48 $ } \\[1 em]x &= \frac{-32}{-48}&& \\[1 em]x &= \frac{2}{3}&& \\[1 em] \end{aligned} $$
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