$$ \begin{aligned} 1^4x\cdot2^2+3^3-\frac{2^5}{4} &= 23&& \text{multiply ALL terms by } \color{blue}{ 4 }. \\[1 em]41^4x\cdot2^2+4\cdot3^3-4 \cdot \frac{2^5}{4} &= 4\cdot23&& \text{cancel out the denominators} \\[1 em]16x+108-32 &= 92&& \text{simplify left side} \\[1 em]16x+76 &= 92&& \text{ move 76 to the right } \\[1 em]16x &= 92-76&& \\[1 em]16x &= 16&& \text{ divide both sides by $ 16 $ } \\[1 em]x &= \frac{16}{16}&& \\[1 em]x &= 1&& \\[1 em] \end{aligned} $$

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