Question
$$(-8k+1)(-8k+1) = 0$$
Answer
$$ k = \dfrac{ 1 }{ 8 } $$
Explanation
$$ \begin{aligned} (-8k+1)(-8k+1) &= 0&& \text{simplify left side} \\[1 em]64k^2-8k-8k+1 &= 0&& \\[1 em]64k^2-16k+1 &= 0&& \\[1 em] \end{aligned} $$
$ 64x^{2}-16x+1 = 0 $ is a quadratic equation.
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