Question
$$(-\frac{5}{4}x+5)(-\frac{5}{4}x+5) = 0$$
Answer
$$ x = 4 $$
Explanation
$$ \begin{aligned} (-\frac{5}{4}x+5)(-\frac{5}{4}x+5) &= 0&& \text{simplify left side} \\[1 em](-\frac{5x}{4}+5)(-\frac{5x}{4}+5) &= 0&& \\[1 em]\frac{-5x+20}{4}\frac{-5x+20}{4} &= 0&& \\[1 em]\frac{25x^2-200x+400}{16} &= 0&& \text{multiply ALL terms by } \color{blue}{ 16 }. \\[1 em]16 \cdot \frac{25x^2-200x+400}{16} &= 16\cdot0&& \text{cancel out the denominators} \\[1 em]25x^2-200x+400 &= 0&& \\[1 em] \end{aligned} $$
$ 25x^{2}-200x+400 = 0 $ is a quadratic equation.
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