Question
$$(-4x)^2x^9 = 29$$
Answer
This equation has no solution.
Explanation
$$ \begin{aligned} (-4x)^2x^9 &= 29&& \text{simplify left side} \\[1 em]16x^2x^9 &= 29&& \\[1 em]16x^{11} &= 29&& \text{move all terms to the left hand side } \\[1 em]16x^{11}-29 &= 0&& \\[1 em] \end{aligned} $$
This polynomial has no rational roots that can be found using Rational Root Test.
Roots were found using Newton method.
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