Question
$$(-4+7i)\cdot(1-i) = 0$$
Answer
$$ \begin{matrix}i_1 = 1 & i_2 = \dfrac{ 4 }{ 7 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (-4+7i)\cdot(1-i) &= 0&& \text{simplify left side} \\[1 em]-4+4i+7i-7i^2 &= 0&& \\[1 em]-7i^2+11i-4 &= 0&& \\[1 em] \end{aligned} $$
$ -7x^{2}+11x-4 = 0 $ is a quadratic equation.
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