Question
$$(-2+6i)\cdot(4+i) = 0$$
Answer
$$ \begin{matrix}i_1 = \dfrac{ 1 }{ 3 } & i_2 = -4 \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (-2+6i)\cdot(4+i) &= 0&& \text{simplify left side} \\[1 em]-8-2i+24i+6i^2 &= 0&& \\[1 em]6i^2+22i-8 &= 0&& \\[1 em] \end{aligned} $$
$ 6x^{2}+22x-8 = 0 $ is a quadratic equation.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this equation.
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