Question
$$(-3a+5)(2a-9) = 0$$
Answer
$$ \begin{matrix}a_1 = \dfrac{ 5 }{ 3 } & a_2 = \dfrac{ 9 }{ 2 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (-3a+5)(2a-9) &= 0&& \text{simplify left side} \\[1 em]-6a^2+27a+10a-45 &= 0&& \\[1 em]-6a^2+37a-45 &= 0&& \\[1 em] \end{aligned} $$
$ -6x^{2}+37x-45 = 0 $ is a quadratic equation.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this equation.
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