$$ \begin{aligned} \frac{4+5-3x\cdot3+10}{5}+2 &= 0&& \text{multiply ALL terms by } \color{blue}{ 5 }. \\[1 em]5 \cdot \frac{4+5-3x\cdot3+10}{5}+5\cdot2 &= 5\cdot0&& \text{cancel out the denominators} \\[1 em]-9x+19+10 &= 0&& \text{simplify left side} \\[1 em]-9x+29 &= 0&& \text{ move the constants to the right } \\[1 em]-9x &= -29&& \text{ divide both sides by $ -9 $ } \\[1 em]x &= \frac{-29}{-9}&& \\[1 em]x &= \frac{29}{9}&& \\[1 em] \end{aligned} $$

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