Question
$$(\frac{12+28}{5}-6)\cdot6 = 0$$
Answer
This equation has no solution.
Explanation
$$ \begin{aligned} (\frac{12+28}{5}-6)\cdot6 &= 0&& \text{simplify left side} \\[1 em](\frac{40}{5}-6)\cdot6 &= 0&& \\[1 em]2\cdot6 &= 0&& \\[1 em]12 &= 0&& \\[1 em] \end{aligned} $$
Since the statement $ \color{red}{ 12 = 0 } $ is FALSE, we conclude that the equation has no solution.
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