To find angle $ \alpha $ use formula:

$$ \sin \left( \frac{ \alpha }{ 2 } \right) = \dfrac{ d_2 }{ d_1 } $$

After substituting $d_2 = 3\, \text{cm}$ and $d_1 = 5\, \text{cm}$ we have:

$$ \sin \left( \frac{ \alpha }{ 2 } \right) = \dfrac{ 3\, \text{cm} }{ 5\, \text{cm} } $$ $$ \sin \left( \frac{ \alpha }{ 2 } \right) = \frac{ 3 }{ 5 } $$ $$ \frac{ \alpha }{ 2 } = \arcsin\left( \frac{ 3 }{ 5 } \right) $$ $$ \frac{ \alpha }{ 2 } = 36.8699^o $$$$ \alpha = 36.8699^o \cdot 2 $$$$ \alpha = 73.7398^o $$

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