STEP 1: find diagonal $ d2 $

To find diagonal $ d2 $ use formula:

$$ d_1^2 + d_2^2 = 4 \cdot a^2 $$

After substituting $d_1 = 30\, \text{cm}$ and $a = 17\, \text{cm}$ we have:

$$ \left( 30\, \text{cm} \right)^{2} + d_2^2 = 4 \cdot \left( 17\, \text{cm} \right)^{2} $$ $$ 900\, \text{cm}^2 + d_2^2 = 1156\, \text{cm}^2 $$ $$ d_2^2 = 1156\, \text{cm}^2 - 900\, \text{cm}^2 $$ $$ d_2^2 = 256\, \text{cm}^2 $$ $$ d_2 = \sqrt{ 256\, \text{cm}^2 } $$$$ d_2 = 16\, \text{cm} $$

STEP 2: find area $ A $

To find area $ A $ use formula:

$$ A = \dfrac{ d_1 \cdot d_2 }{ 2 } $$

After substituting $d_1 = 30\, \text{cm}$ and $d_2 = 16\, \text{cm}$ we have:

$$ A = \dfrac{ 30\, \text{cm} \cdot 16\, \text{cm} }{ 2 }$$$$ A = \dfrac{ 480\, \text{cm}^2 }{ 2 } $$$$ A = 240\, \text{cm}^2 $$

STEP 3: find height $ h $

To find height $ h $ use formula:

$$ A = a \cdot h $$

After substituting $A = 240\, \text{cm}^2$ and $a = 17\, \text{cm}$ we have:

$$ 240\, \text{cm}^2 = 17\, \text{cm} \cdot h $$$$ h = \dfrac{ 240\, \text{cm}^2 }{ 17\, \text{cm} } $$$$ h = \frac{ 240 }{ 17 }\, \text{cm} $$

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