Question
Find the area $ A $ of a rhombus if diagonal $d_1 = 4 \sqrt{ 3 }\, \text{cm}$ and diagonal $d_2 = 4 \sqrt{ 2 }\, \text{cm}$.
Answer
$8 \sqrt{ 6 }\, \text{cm}^2$
Explanation
To find area $ A $ use formula:
$$ A = \dfrac{ d_1 \cdot d_2 }{ 2 } $$After substituting $d_1 = 4 \sqrt{ 3 }\, \text{cm}$ and $d_2 = 4 \sqrt{ 2 }\, \text{cm}$ we have:
$$ A = \dfrac{ 4 \sqrt{ 3 }\, \text{cm} \cdot 4 \sqrt{ 2 }\, \text{cm} }{ 2 }$$$$ A = \dfrac{ 16 \sqrt{ 6 }\, \text{cm}^2 }{ 2 } $$$$ A = 8 \sqrt{ 6 }\, \text{cm}^2 $$This page was created using
Rhombus Calculator