Question
Find the side $ a $ of a rhombus if diagonal $d_1 = 2\, \text{cm}$ and diagonal $d_2 = 2\, \text{cm}$.
Answer
$\sqrt{ 2 }\, \text{cm}$
Explanation
To find side $ a $ use formula:
$$ d_1^2 + d_2^2 = 4 \cdot a^2 $$After substituting $d_1 = 2\, \text{cm}$ and $d_2 = 2\, \text{cm}$ we have:
$$ \left( 2\, \text{cm} \right)^{2} + \left( 2\, \text{cm} \right)^{2} = 4 \cdot a^2 $$ $$ 4\, \text{cm}^2 + 4\, \text{cm}^2 = 4 \cdot a^2 $$ $$ 4 \cdot a^2 = 8\, \text{cm}^2 $$ $$ a^2 = \frac{ 8\, \text{cm}^2 }{ 4 } $$ $$ a^2 = 2\, \text{cm}^2 $$ $$ a = \sqrt{ 2\, \text{cm}^2 } $$$$ a = \sqrt{ 2 }\, \text{cm} $$This page was created using
Rhombus Calculator