Question
Answer
$$\dfrac{\sqrt{7}}{\sqrt{63}}=\dfrac{1}{3}$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}\frac{\sqrt{7}}{\sqrt{63}}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{\sqrt{7}}{\sqrt{63}}\frac{\sqrt{63}}{\sqrt{63}} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}\frac{21}{63} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}} \frac{ 21 : \color{orangered}{ 21 } }{ 63 : \color{orangered}{ 21 }} \xlongequal{ } \\[1 em] & \xlongequal{ }\frac{1}{3}\end{aligned} $$ | |
| ① | Multiply the numerator and denominator by the conjugate of the denominator . $$\color{blue}{ \sqrt{63}} $$. |
| ② | Multiply in a numerator. $$ \color{blue}{ \sqrt{7} } \cdot \sqrt{63} = 21 $$ Simplify denominator. $$ \color{blue}{ \sqrt{63} } \cdot \sqrt{63} = 63 $$ |
| ③ | Divide both the top and bottom numbers by $ \color{orangered}{ 21 } $. |
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