Question
Answer
$$\dfrac{\sqrt{68}}{\sqrt{8}\cdot\sqrt{17}}=\dfrac{\sqrt{2}}{2}$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}\frac{\sqrt{68}}{\sqrt{8}\cdot\sqrt{17}}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{\sqrt{68}}{\sqrt{8}\cdot\sqrt{17}}\frac{\sqrt{136}}{\sqrt{136}} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}\frac{68\sqrt{2}}{136} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}\frac{\sqrt{2}}{2}\end{aligned} $$ | |
| ① | Multiply the numerator and denominator by the conjugate of the denominator . $$\color{blue}{ \sqrt{136}} $$. |
| ② | Multiply in a numerator. $$ \color{blue}{ \sqrt{68} } \cdot \sqrt{136} = 68 \sqrt{2} $$ Simplify denominator. $$ \color{blue}{ \sqrt{136} } \cdot \sqrt{136} = 136 $$ |
| ③ | Divide both numerator and denominator by 68. |
This page was created using
Rationalize Denominator Calculator