Question
Answer
$$\dfrac{\sqrt{65}}{\sqrt{81}}=\dfrac{\sqrt{65}}{9}$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}\frac{\sqrt{65}}{\sqrt{81}}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{\sqrt{65}}{\sqrt{81}}\frac{\sqrt{81}}{\sqrt{81}} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}\frac{9\sqrt{65}}{81} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}\frac{\sqrt{65}}{9}\end{aligned} $$ | |
| ① | Multiply the numerator and denominator by the conjugate of the denominator . $$\color{blue}{ \sqrt{81}} $$. |
| ② | Multiply in a numerator. $$ \color{blue}{ \sqrt{65} } \cdot \sqrt{81} = 9 \sqrt{65} $$ Simplify denominator. $$ \color{blue}{ \sqrt{81} } \cdot \sqrt{81} = 81 $$ |
| ③ | Divide both numerator and denominator by 9. |
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