Question
Answer
$$\dfrac{\sqrt{6}^3}{\sqrt{10}^3}=\dfrac{3\sqrt{15}}{25}$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}\frac{\sqrt{6}^3}{\sqrt{10}^3}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}\frac{6\sqrt{6}}{10\sqrt{10}} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}\frac{6\sqrt{6}}{10\sqrt{10}}\frac{\sqrt{10}}{\sqrt{10}} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle4}{\textcircled {4}} } }}}\frac{12\sqrt{15}}{100} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle5}{\textcircled {5}} } }}}\frac{ 12 \sqrt{ 15 } : \color{blue}{ 4 } } { 100 : \color{blue}{ 4 }} \xlongequal{ } \\[1 em] & \xlongequal{ }\frac{3\sqrt{15}}{25}\end{aligned} $$ | |
| ① | $$ \sqrt{6}^3 =
\sqrt{6} ^2 \cdot \sqrt{6} =
\lvert 6 \rvert \cdot \sqrt{6} =
6\sqrt{6} $$ |
| ② | $$ \sqrt{10}^3 =
\sqrt{10} ^2 \cdot \sqrt{10} =
\lvert 10 \rvert \cdot \sqrt{10} =
10\sqrt{10} $$ |
| ③ | Multiply the numerator and denominator by the conjugate of the denominator . $$\color{blue}{ \sqrt{10}} $$. |
| ④ | Multiply in a numerator. $$ \color{blue}{ 6 \sqrt{6} } \cdot \sqrt{10} = 12 \sqrt{15} $$ Simplify denominator. $$ \color{blue}{ 10 \sqrt{10} } \cdot \sqrt{10} = 100 $$ |
| ⑤ | Divide numerator and denominator by $ \color{blue}{ 4 } $. |
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