Question
Answer
$$\dfrac{\sqrt{432}}{\sqrt{12}}=6$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}\frac{\sqrt{432}}{\sqrt{12}}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{\sqrt{432}}{\sqrt{12}}\frac{\sqrt{12}}{\sqrt{12}} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}\frac{72}{12} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}} \frac{ 72 : \color{orangered}{ 12 } }{ 12 : \color{orangered}{ 12 }} \xlongequal{ } \\[1 em] & \xlongequal{ }\frac{6}{1} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle4}{\textcircled {4}} } }}}6\end{aligned} $$ | |
| ① | Multiply the numerator and denominator by the conjugate of the denominator . $$\color{blue}{ \sqrt{12}} $$. |
| ② | Multiply in a numerator. $$ \color{blue}{ \sqrt{432} } \cdot \sqrt{12} = 72 $$ Simplify denominator. $$ \color{blue}{ \sqrt{12} } \cdot \sqrt{12} = 12 $$ |
| ③ | Divide both the top and bottom numbers by $ \color{orangered}{ 12 } $. |
| ④ | Remove 1 from denominator. |
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